If $$sin2$$⁡$$(x+$$π$$/4)+3cos$$⁡$$2x$$>$$0$$, then

Correct option is 1cos⁡(2x−π/6)>−1/2

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If $\sin^{2} (x + π / 4) + \sqrt{3} \cos 2 x > 0,$ then

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cos⁡(2x−π/6)>−1/2

sin⁡(2x−π/6)<−1/2

sin⁡(2x−π/6)>−1/2

cos⁡(2x−π/6)<−1/2

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detailed solution

Correct option is A

2sin2⁡(x+π/4)+3cos⁡2x>0⇒1−cos⁡(2x+π/2)+3cos⁡2x>0⇒12sin⁡2x+32cos⁡2x>−12⇒cos⁡(2x−π/6)>−12

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If sin2⁡(x+π/4)+3cos⁡2x>0, then

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If $\sin^{2} (x + π / 4) + \sqrt{3} \cos 2 x > 0,$ then