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Questions  

 If sinx+cosx+tanx+cosecx+secx+cotx=7,  then sin2x=

a
22+87
b
22−87
c
11
d
22

detailed solution

Correct option is B

sinx+cosx+1sinxcosx+sinx+cosxsinxcosx=7⇒ sinx+cosx1+1sinxcosx=7−1sinxcosxSquaring on both sides we get⇒sin2xsin22x-44sin2x+36=0sin2x≠0⇒sin2x=22-87

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