If sinx+cosx+tanx+cosecx+secx+cotx=7, then sin2x=
22+87
22−87
11
22
sinx+cosx+1sinxcosx+sinx+cosxsinxcosx=7
⇒ sinx+cosx1+1sinxcosx=7−1sinxcosx
Squaring on both sides we get
⇒sin2xsin22x-44sin2x+36=0sin2x≠0⇒sin2x=22-87