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Questions  

If sin4x2+cos4x3=15 then

a
tan2⁡x+43
b
sin8⁡x8+cos8⁡x27=1125
c
tan2⁡x=13
d
sin8⁡x8+cos8⁡x27=2125

detailed solution

Correct option is B

we have ,   sin4⁡x2+cos4⁡x3=15sin4⁡x2+1−sin2⁡x23=153sin4⁡x+21−sin2⁡x2=6525sin4⁡x−20sin2⁡x+4=0sin2⁡x=25cos2⁡x=3/5tan2⁡x=2/3sin8⁡x8+cos8⁡x27=(2/5)48+(3/5)427=2625+3625=5625=1125

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