First slide
Introduction to integration
Question

If 21+sinxdx=4cos(ax+b)+C then the value of a, b are respectively

Moderate
Solution

Let,

I=21+sinxdx=2sinx2+cosx2dx=2sinπ4+x2dx=4cosx2+π4+C

But,  I=4cos(ax+b)+C

on comparing' we get 

a=12, b=π4

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