If ∫21+sinxdx=−4cos(ax+b)+C, then the value of a, b are respectively
12,π4
1,π2
1,1
None of these
Let,
I=∫21+sinxdx=2∫sinx2+cosx2dx=2∫sinπ4+x2dx=−4cosx2+π4+C
But, I=−4cos(ax+b)+C
on comparing' we get
a=12, b=π4