First slide
Properties of ITF
Question

If sin1x+sin1y+sin1z=3π2 then the value of x100+y100+z1003x101+y101+z101 is

Easy
Solution

We have sin–1x + sin–1y + sin–1z = 3π2 it is possible only when
sin1x=π2x=1 sin1xπ2sin1y=π2y=1; sin1z=π2z=1x100+y100+z1003x101+y101+z101=1+1+133=31=2

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