If sin3x sin3x=∑r=0narcosrx is an identity then n+a1=
0
6
-6
4
a0cos0x+a1cosx+..........+ancosnx=sin3xsin3x=143sinx−sin3xsin3x=382sin3xsinx-181−cos6x=38cos2x−cos4x-181−cos6x=-18+38cos2x-38cos4x+18cos6xComparing,we get a0=-18, a1=0, n=6 ∴a1+n=6