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If $1 + \sin x + \sin^{2} x + \sin^{3} x + \dots + \dots \infty$ is equal to $4 + 2 \sqrt{3},$ $0 < x < π,$ then $x =$

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π6

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Correct option is D

We have,00Now,1+sin⁡x+sin2⁡x+…x=4+23⇒11−sin⁡x=4+23⇒sin⁡x=1−14+23⇒sin⁡x=3+234+23=32⇒x=π3 or, 2π3

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If 1+sin⁡x+sin2⁡x+sin3⁡x+…+…∞ is equal to 4+23,0<x<π, then x=

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Ready to Test Your Skills?

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If $1 + \sin x + \sin^{2} x + \sin^{3} x + \dots + \dots \infty$ is equal to $4 + 2 \sqrt{3},$ $0 < x < π,$ then $x =$