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Questions  

If sin1x+sin1y=π2, then  1+x4+y4x2x2y2+y2is equal to

a
1
b
2
c
12
d
None of these

detailed solution

Correct option is B

sin−1x+sin−1y=π2⇒sin−1x=π2−sin−1y=cos-1y⇒sin−1x=sin−11−y2⇒x=1-y2⇒x2+y2=1∴1+x4+y4x2−x2y2+y2=1+(x2+y2)2−2x2y21−x2y2                                         =1+1−2x2y21−x2y2 =2

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