If sin⁡xsin⁡y=12,cos⁡xcos⁡y=32, where x,y∈0,π2, then the value of tan(x + y) is equal to

sin⁡xsin⁡y=12,cos⁡xcos⁡y=32⇒ tan⁡xtan⁡y=13⇒ tan⁡(x+y)=tan⁡x+tan⁡y1−tan⁡xtan⁡y=4tan⁡x1−3tan2⁡xAlso  sin⁡y=2sin⁡x,cos⁡y=23cos⁡xor sin2⁡y+cos2⁡y=4sin2⁡x+4cos2⁡x9=1or 36tan2⁡x+4=9sec2⁡x=91+tan2⁡xor  27tan2⁡x=5or  tan⁡x=533⇒tan⁡(x+y)=45331−1527=45×2712×33=15