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If $\int_{\sin x}^{1} t^{2} f (t) d t = 1 - \sin x,$ then $f (1 / \sqrt{3})$ is equal to

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Correct option is D

Differentiating both the sides, we obtain⇒ f(sin⁡ x)=1sin2⁡ x, if cos⁡ x≠0⇒ f(sin⁡x)=1sin2⁡x, if cos⁡ x≠0If sin⁡ x=1/3 then cos⁡ x≠0 so f(1/3)=3.

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If ∫sin⁡ x1 t2f(t)dt=1−sin⁡ x, then f(1/3) is equal to

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If $\int_{\sin x}^{1} t^{2} f (t) d t = 1 - \sin x,$ then $f (1 / \sqrt{3})$ is equal to