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If $\sin (y + z - x), \sin (z + x - y), \sin (x + y - z)$ are in A.P., then tan x, tan y, tan z are in

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Correct option is A

Applying b- a= c-b for A.P., we get2cos⁡zsin⁡(x−y)=2cos⁡xsin⁡(y−z)Dividing by 2 cosx cosy cosz, etc., we gettanx-tany = tany-tanz

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If sin⁡(y+z−x),sin⁡(z+x−y),sin⁡(x+y−z) are in A.P., then tan x, tan y, tan z are in

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If $\sin (y + z - x), \sin (z + x - y), \sin (x + y - z)$ are in A.P., then tan x, tan y, tan z are in