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If A is singular matrix, then adj A is 

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a
singular
b
non-singular
c
symmetric
d
not defined

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detailed solution

Correct option is A

Since A is  singular __|A|=0|adjA|=|A|n−1|adjA|=0n−1∣ adj A∣=0⇒AdjA is singular


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Let A be a square matrix of order 3 such that |Adj A|=100, then |A| equals 


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