First slide
Introduction to ITF
Question

If the solution set of inequality (cot-1x) (tan-1x)+(2-π2)cot-1x-3tan-1 x-3(2-π2)>0 is (a,b),  then the value of cot-1 a+cot-1b is 

Moderate
Solution

 (cot-1x) (tan-1x)+(2-π2)cot-1x-3tan-1 x-3(2-π2)>0  cot-1x (tan-1x+2-π2)-3(tan-1 x+2-π2)>0  (cot-1x-3) (tan-1x+2-π2)>0   Since tan-1x-π2 =-cot-1x,  (cot-1x-3)(2-cot-1x) >0 (cot-1x-3)(cot-1x-2) <0  2<cot-1x<3 cot 3<x<cot 2                    since it is decreasing functionHence x(cot3,cot2)  cot-1 a+cot-1b= cot-1 (cot3)+cot-1(cot2)                              =3+2                              =5

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