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$If A is the square matrix order 3 such that | A | = 2, then | a d j (adj (adj A)) | is$

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Correct option is B

We know that |adj⁡(adj⁡A)|=|A|(n−1)2⇒|adj⁡(adj⁡(adjA))|=|adj⁡A|(n−1)2=|A|(n−1)3=28=256

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If A is the square matrix order 3 such that |A|=2, then |adj(adj⁡(adj⁡A))| is

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$If A is the square matrix order 3 such that | A | = 2, then | a d j (adj (adj A)) | is$