Q.
If A is a square matrix such that (A−2I)(A+I)=0 ,then A−1=
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a
A−I2
b
A+I2
c
2(A−I)
d
2A+I
answer is A.
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Detailed Solution
(A−2I)(A+I)=0 AA−2AI+AI−2I=0 (∵ AI=A)AA-AI=2I⇒A(A−I2)=I ∵A−I2=A−1
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