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If square matrix A is such that 3A3+2A2+5A + I = O, then A1 is equal to

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a
3A2+2A+5I
b
−3A2+2A+5I
c
3A2−2A−5I
d
none of these

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detailed solution

Correct option is B

We have  A3A2+2A+5I=−I∴ A−1=−3A2+2A+5I [∴ Inverse of a matrix is unique]


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