If square matrix A is such that 3A3+2A2+5A + I = O, then A−1 is equal to
3A2+2A+5I
−3A2+2A+5I
3A2−2A−5I
none of these
We have A3A2+2A+5I=−I
∴ A−1=−3A2+2A+5I [∴ Inverse of a matrix is unique]