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Q.

If the squares of a 8 x 8 chessboard are painted either red or black at random. The probability that not all the squares in any column are alternating in color isThe probability that the chessboard contains equal number of red and black squares isThe probability that all the squares in any column are of same color and that of a row are of alternating cotror is

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a

1−1/278

b

1/256

c

1−1/27

d

none of these

e

64C32264

f

64!32!⋅264

g

232−1264

h

none of these

i

1/264

j

1/263

k

1/2

l

none of these

answer is , , .

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Detailed Solution

The total number of ways of painting first column when colors are not alternating is 28 - 2. The total number of ways when no column has alternating colors is (28 - 2)8/264.The number of ways the square has equal number of red and black squares is  64C32. Hence, the required probability is  64C32/264.This is possible only when the column are alternating red and black. Hence, the required probability is 2/264 = 1/263.
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If the squares of a 8 x 8 chessboard are painted either red or black at random. The probability that not all the squares in any column are alternating in color isThe probability that the chessboard contains equal number of red and black squares isThe probability that all the squares in any column are of same color and that of a row are of alternating cotror is