If the standard deviation of the data 1, 3, 5,7, ... , 2017 is σ then σ is (where . denotes the greatest interger function)

Let X¯ be the mean of the given data. Then,X¯=1+3+5+7+…+2017109=(109)2109=109∴    Variance σ2=1100912+32+…+20172−(1009)2⇒    σ2=339360∴    σ=582.54Hence, [σ]=582