First slide

Introduction to statistics

Question

If the standard deviation of 0, 1,2,3, .. .,9 is K, then the standard deviation of 10, 11, 12, 13, . . ., 19 is

Easy

A

K
B

K+10
C

K+ $\sqrt{10}$
D

10 K

Solution

S.D =K= $\sqrt{\frac{n^{2} - 1}{12}}, w h e r e n = 20 f o r b o t h t h e g i v e n d a t a$

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