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Questions  

If the standard deviation of x1,x2,,xn is 3.5, then the standard deviation of 2x13,2x23,2xn3 is

a
-7
b
-4
c
7
d
1.75

detailed solution

Correct option is C

If di=xi−Ahthen, σx=|h|σdNow, −2xi−3=xi+32−12Here,  h=−12σd=1|h|σx=2×3.5=7

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