If a straight line perpendicular to 3x-4y-6=0 forms a triangle with the coordinate axes whose area is 6sq. units, then the equation of the straight line (s) is
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a
x-2y=6
b
4x+3y=12
c
4x+3y+24=0
d
3x-4y=12
answer is B.
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Detailed Solution
The line perpendicular to given line is 4x+3y = k ∴k224=6