If the straight line ax+by+c=0make a triangle of constant area with coordinate axes, then
a,b,c are in G.P.
a, c, b are in G.P.
c, a, b are in G.P.
none of these
Line ax+by+c=0 meets the coordinate axes at A(-c/a, 0) and (0, -c/b)
∴ Area of ΔOAB=12×OA×OB
⇒ Area of ΔOAB=12×−ca−cb=c2
Clearly, this will be constant, if a, c, b arc in G.P.