If the straight line x−2y+1=0 intersects the circle x2+y2=25 in points P and Q, then the coordinates of the point of intersection of tangents drawn at P and Q to the circle x2+y2=25 are

Let R(h,k) be the point of intersection of tangents drawn at P and Q to the given circle. Then, PQ is the chord of contact of tangents drawn from R to x2+y2=25 So its equation is hx+ky−25=0.                  …(i)It is given that the equation of PQ isx−2y+1=0                          …(ii)Since (i) and (ii) represent the same line. ∴ h1=k−2=−251⇒h=−25,k=50Hence, the required point is (- 25, 50).