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If the straight line x2y+1=0 intersects the circle x2+y2=25 in points P and Q, then the coordinates of the point of intersection of tangents drawn at P and Q to the circle x2+y2=25 are

a
(25,50)
b
(−25,−50)
c
(−25,50)
d
(25,−50)

detailed solution

Correct option is C

Let R(h,k) be the point of intersection of tangents drawn at P and Q to the given circle. Then, PQ is the chord of contact of tangents drawn from R to x2+y2=25 So its equation is hx+ky−25=0.                  …(i)It is given that the equation of PQ isx−2y+1=0                          …(ii)Since (i) and (ii) represent the same line. ∴ h1=k−2=−251⇒h=−25,k=50Hence, the required point is (- 25, 50).

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