Questions
If the straight line intersects the circle in points and , then the coordinates of the point of intersection of tangents drawn at and to the circle are
detailed solution
Correct option is C
Let R(h,k) be the point of intersection of tangents drawn at P and Q to the given circle. Then, PQ is the chord of contact of tangents drawn from R to x2+y2=25 So its equation is hx+ky−25=0. …(i)It is given that the equation of PQ isx−2y+1=0 …(ii)Since (i) and (ii) represent the same line. ∴ h1=k−2=−251⇒h=−25,k=50Hence, the required point is (- 25, 50).Talk to our academic expert!
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The area of the quadrilateral formed by the tangents from the point (2, -1) to the circle
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