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If the straight lines x = 1 + s, y = –3 –λ s, z = 1 +λ s and x=t2,y=1+t,z=2−t with parameters ‘s’ and ‘t’ respectively are coplanar then λ =

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answer is -2.

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Detailed Solution

Given lines are x−11=y+3−λ=z−1λ,x12=y−11=z−2−1Given lines are coplanar⇒1−4−11−λλ121−1=0, ⇒λ=−2

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