Questions

If the straight lines $\frac{x-1}{2}=\frac{y+1}{k}=\frac{z}{2}$ and $\frac{x+1}{5}=\frac{y+1}{2}=\frac{z}{k}$ are coplanar, then the plane (s) containing these two lines is (are)

60 mins Expert Faculty Ask Questions

a

y+2z=-1

b

y+z=-1

c

y-z=-1

d

y-2z=-1

detailed solution

Correct option is B

For given lines to be coplanar, we should have 2002k252k=0⇒k=±2For k = 2, obviously the plane y+1=z is common in both lines.For k = -2, the plane is given by x−1y+1z2−2252−2=0⇒y+z+1=0

Similar Questions

A ray of light comes along the line Z = 0 and strikes the plane mirror kept along the plane P = 0 at B. A(2,1,6) is a point on the line Z=0 whose image about P=0 is, A'. It is given that L=0 is $\frac{x-2}{3}=\frac{y-1}{4}=\frac{z-6}{5}$ and p= 0 is x+y-2z=3.

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