If the straight lines x+y−2=0,2x−y+1=0, and ax+by−c=0 are concurrent, then the family of lines
2ax+3by+c=0(a,b,c are nonzero ) is concurrent at
(2,3)
(1/2,1/3)
(-1/6 ,- 5/9)
(2/3,-7/5)
Given that three lines are concurrent hence,
11−22−11ab−c=0Expand the determinant, we get or a+5b−3c=0 or −a3−53b+c=0 ---(1)
2ax+3by+c=0----(2) comparing (1) and (2)
hence the straight lines are concurrent at 2x=−13 and 3y=−53
So, x=−16,y=−59