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Questions  

 If the sum of the coefficients in the expansion of (x2y+3z)n,n is 128 , then the  greatest coefficient in the expansion of (1+x)n is 

a
35
b
20
c
10
d
15

detailed solution

Correct option is A

Sum of the coefficients in the expansion(x−2y+3z)n is (1−2+3)n=2n (∵ Put x=y=z=1) i.e. 2n=128⇒n=7 therefore, greatest coefficient in the expansion of (1+x)7 is 7C3 or 7C4⇒7C3=7C4=35

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