First slide
Binomial theorem for positive integral Index
Question

 If the sum of the coefficients in the expansion of (x2y+3z)n,n is 128 , then the  greatest coefficient in the expansion of (1+x)n is 

Moderate
Solution

Sum of the coefficients in the expansion

(x2y+3z)n is (12+3)n=2n ( Put x=y=z=1) i.e. 2n=128n=7

 therefore, greatest coefficient in the expansion of (1+x)7 is 7C3 or 7C47C3=7C4=35

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