. If the sum of deviations of a number of observations about 4 is 30 and that about 3 is 40. Then, mean of the observations is
7
10
11
None of these
Given that,∑i=1n xi−4=30
and ∑i=1n xi−3=40
i.e..,Σxi−4n=30 (i)
and Σxi−3n=40 ..(ii)
On solving Eqs. (i) and (ii), we get
n=10 and Σxi=70∴∑i=1n xi Mean =110(70)=7