If the sum of the distances of a point from two perpendicular lines in a plane is 1 , then its locus is

Let the two perpendicular lines be the coordinate axes. Let (x, y) be the point, sum of whose distances from two axes is1. Then we must have |x|+|y|=1 or  ±x±y=1The four lines are x+y=1,x−y=1,−x+y=1,−x−y=1Any two adjacent sides are perpendicular to each other. Also, each line is equidistant from the origin. Therefore, the figure formed is a square.