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If the sum of first n terms of two A.P.’s are in the ratio 3n + 8 : 7n + 15, then the ratio of 12th term is

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a
8 : 7
b
7 : 16
c
74 : 169
d
13 : 47

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detailed solution

Correct option is C

Let two A.P.’s bea,a+d,a+2d,…and A,A+D,A+2D,…We are givenn2[2a+(n−1)d]n2[2A+(n−1)D]=3n+87n+15⇒a+n−12dA+n−12D=3n+87n+15 Put (n−1)/2=11 or n=23.∴ a+11dA+11D=3(23)+87(23)+15=77176=716


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If the sum of first n terms of an AP is cn2, then the sum of squares of these  n terms is 


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