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If the sum of the first ten terms of the series ${(1 \frac{3}{5})}^{2} + {(2 \frac{2}{5})}^{2} + {(3 \frac{1}{5})}^{2} + 4^{2} + {(4 \frac{4}{5})}^{2} + \dots . is \frac{16}{5} m, then m is equal to$

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Correct option is C

852+1252+1652+2152+2452+....S=422512+22+32+42+…112−1=1625(11)(12)(23)6−1=1625[505]=165mm=101

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If the sum of the first ten terms of the series 1352+2252+3152+42+4452+…. is 165m, then m is equal to

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If the sum of the first ten terms of the series ${(1 \frac{3}{5})}^{2} + {(2 \frac{2}{5})}^{2} + {(3 \frac{1}{5})}^{2} + 4^{2} + {(4 \frac{4}{5})}^{2} + \dots . is \frac{16}{5} m, then m is equal to$