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If sum of first 20 terms of an A.P. is equal to sum of first 30 terms of the A.P. then sum of the first 50 terms of the A.P. is
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a
-1
b
0
c
10
d
25
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Correct option is B
Let a be the first term and d be the commondifference of the A.P., thenS20=S30⇒ 202[2a+(20−1)d]=302[2a+(30−1)d]⇒ 2a+49d=0Now, S50=502[2a+(50−1)d]=0.Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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