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If sum of the infinite G.P. is 49/6, then sum of the 3rd term and the 4th term of the G.P. is
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a
849
b
17
c
67
d
2349
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Correct option is A
For p > 1, 496=p+1+1p+1p2+…=p1−1/p ⇒ 496=p2p−1⇒ 6p2−49p+49=0⇒ 6p2−42p−7p+49=0⇒ (6p−7)(p−7)=0As p > 2, p = 7Thus, a3+a4=p1p2+p1p3 =17+149=849Similar Questions
Sum of an infinite G.P. is 2 and sum of their cubes is 24, then 5th term of the G.P. is
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