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If the sum to n terms of an A.P. is 3n2+5n ,while 

 Tm=164 then value of m is

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a
25
b
26
c
27
d
28

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detailed solution

Correct option is C

Tm=Sm−Sm−1⇒164=3m2+5m−3(m−1)2+5(m−1) =6m+2⇒ m=27


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