If the sum of odd terms and the sum of even terms in the expansion of (x+a)n
are p and q respectively then p2+q2=
x2+a2n
x2-a2n
12x+a2n+x-a2n
12x+a2n−x-a2n
p2+q2=12(p+q)2+(p−q)2=12(x+a)2n+(x−a)2n