Questions
If the sum of the series 2, 5, 8, 11, ………. n terms is 60100, then find the value of n.
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a
100
b
200
c
300
d
400
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Correct option is B
Here first term is a=2 and common difference d=3.Hence sum of n terms of A.P. is (n/2)(4+3(n-1))=60100⇒3n2+n−120200=0⇒(n−200)(3n+601)=0⇒n=200Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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