If the sum of the series 2, 5, 8, 11, ………. n terms is 60100, then find the value of n.
100
200
300
400
Here first term is a=2 and common difference d=3.
Hence sum of n terms of A.P. is (n/2)(4+3(n-1))=60100
⇒3n2+n−120200=0⇒(n−200)(3n+601)=0⇒n=200