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If the sum of the squares of the distance of a point from the three coordinate axes be 36, then its distance from the origin is
detailed solution
Correct option is B
. Let P(x, y,z)be any point in the plane. According to the given condition, (distance from P to X-axis)2 + (distance from P to Y-axis)2 + (distance from P to Z-axis)2 = 36⇒ y2+z22+x2+z22+x2+y22=36⇒ y2+z2+x2+z2+x2+y2=36⇒ 2x2+y2+z2=36⇒ x2+y2+z2=18----iThe distance from origin to the point (x, y, z) is=x2+y2+z2=18 [∵ from Eq. (i)] =32Talk to our academic expert!
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