If the sum of the squares of the distance of a point from the three coordinate axes be 36, then its distancefrom the origin is
5
32
21
33
Let P(x, y, z).Now under given condition, we get
x2+y22+y2+z22+z2+x22=36⇒ x2+y2+z2=18
Then distance from origin to the point (x, y, z) is
x2+y2+z2=18=32