If the sum of three numbers in A.P. is 24 and their product is 440, then common difference of the
A.P. can be
3
2
5
-5
Let the three number in A.P. be a–d, a, a+d.
Then
24=(a−d)+a+(a+d)=3a⇒ a=8
Also, 440 = (a – d) a(a + d) = 8(64 – d2 )
⇒ d2=64−55=9⇒d=±3.
∴ d can be 3.