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If the sum of three numbers in A.P. is 24 and their product is 440, then common difference of the

A.P. can be

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a
3
b
2
c
5
d
-5

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detailed solution

Correct option is A

Let the three number in A.P. be a–d, a, a+d.Then       24=(a−d)+a+(a+d)=3a⇒     a=8Also, 440 = (a – d) a(a + d) = 8(64 – d2 )⇒    d2=64−55=9⇒d=±3. ∴    d can be 3.


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