If the sum of two roots of the equation x3−px2+qx−r=0 is zero, then
pq=r
qr=p
pr=q
pqr =1
Let the roots of the given equation be α,β,γ such that
α+β=0 Then,
α+β+γ=−(−p)1⇒α+β+γ=p⇒γ=p[∵α+β=0]
Hence, the real root of ax3+bx2+cx+d=0 is da