If the sum of two roots of the equation x3−px2+qx−r=0 is zero, then

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pq=r

qr=p

pr=q

pqr =1

answer is A.

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Detailed Solution

Let the roots of the given equation be α,β,γ such that α+β=0 Then,α+β+γ=−(−p)1⇒α+β+γ=p⇒γ=p[∵α+β=0] Hence, the real root of ax3+bx2+cx+d=0 is da

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