If the sum of two of the roots of x3+px2+qx+r=0 is zero, then pq=
-r
2r
-2r
r
Given that, α+β=0α+β+γ=−p⇒γ=−p
Substituting γ=−p in the given equation ⇒ −p3+p3−pq+r=0⇒pq=r