If the sum of two of the roots of x3+px2+qx+r=0 is zero, then pq=
-r
r
2r
-2r
Given that, α+β=0
α+β+γ=-p⇒γ=-p
Substituting γ=-p in the given equation
⇒-p3+p3-pq+r⇒pq=r