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 If the system of equation x+2y3z=1,(P+2)z=3,(2P+1)y+z=2 is inconsistent, then the value of P is

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a
-2
b
−12
c
0
d
-2 or−12

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detailed solution

Correct option is A

Δ=0⇒P=−2 or −12 Put, if P=−12, then Δ1=Δ2=Δ3=0∴P=−2


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