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If the system of equations (k+1)x+(k+2)3y=(k+3)3(k+1)x+(k+2)y=k+3,  x+y=1 is consistent, then k=__________

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a
2
b
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c
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d
-1

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detailed solution

Correct option is B

⇒a3b3c3abc111=0 wherea=k+1,b=k+2,c=k+3⇒(a−b)(b−c)(c−a)[a+b+c]=0⇒a+b+c=0⇒k+1+k+2+k+3=0⇒3k=−6⇒k=−2


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