Q.

If the system of equations  (k+1)3x+(k+2)3y=(k+3)3,  (k+1)x+(k+2)y=k+3,  x+y=1  is consistent. Then the value of k is

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answer is -2.

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Detailed Solution

k+13k+23k+33k+1k+2k+3111=0⇒k=−2
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