Q.
If the system of equations kx+y+2z=1,3x−y−2z=2,−2x−2y−4z=3 has infinitely many solutions, then k is equal to_________.
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 21.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Δ=k123-1-2-2-2-4=0 and Δ3=k113-12-2-23=0⇒k=21 Remaining two determinants are equal to zero, when k=21 all determinants are equal to zero, then the system has infinitely many solutions