If the system of equations λx+(b−a)y+(c−a)z=0, (a−b)x+λy+(c−b)z=0 and (a−c)x+(b−c)y+λx=0 has a non-trivial solutions, then the value of λ is
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a
λ=0
b
λ=1
c
λ=−1
d
None of these
answer is A.
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Detailed Solution
As the given system of equations has non-trivial ⇒ |λ b−a c−aa−b λ c−ba−c b−c λ|=0 Whenλ=0, then determinant becomes skew-symmetric determinants of odd order, which is equal to zero. Thus, λ=0.