If the system of equations x=cy+bz,y=az+cx,z=bx+ay has a nonzero solution then a2+b2+c2+2abc=
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x=cy+bz,y=az+cx,z=bx+ay⇒−1cbc−1aba−1xyz=000
Given equations has non zero solution ⇒−1cbc−1aba−1=0
⇒−11−a2−c(−1−ab)+b(ac+b)=0⇒−1+a2+c2+abc+abc+b2=0⇒a2+b2+c2+2abc=1