First slide
System of linear equations
Question

If the system of equations x=cy+bz,y=az+cx,z=bx+ay  has a nonzero solution then  a2+b2+c2+2abc=

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Solution

x=cy+bz,y=az+cx,z=bx+ay1cbc1aba1xyz=000

 Given equations has non zero solution 1cbc1aba1=0

11a2c(1ab)+b(ac+b)=01+a2+c2+abc+abc+b2=0a2+b2+c2+2abc=1

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