If the system of equations x−ky−z=0,kx−y−z=0,x+y−z=0 has a non-zero solution, then the possible values of k are
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
-1, 2
b
1, 2
c
0, 1
d
-1, 1
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
As the given system has a non-zero solution, 0=1−k−1k−1−111−1=1+k−k−1−11+k−2−100−1 [Using C1→C1−C2,C2→C2+C3]⇒ 0 =(−1)[(1+k)(−2)−(1+k)(−k−1)]⇒ 0 =(1+k)(−2+k+1)⇒k=−1,1