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If the system of equations xkyz=0.kxyz=0,x+yz=0 has a non-zero solution then the possible value of ‘k’ are

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a
-1,2
b
1,2
c
0,1
d
-1,1

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detailed solution

Correct option is D

The condition for a homogeneous system to have a non-zero solution is Δ=o⇒1-k-1k-1-111-1=0          C1→ C1+ C3 ⇒0-k-1k-1-1-101-1=0 ⇒k-1k+1=0 ⇒k=1,-1


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